Trial Project

In the nitration of benzene using a moisture of Conc \(\begin{align}{{H}_{2}}S{{O}_{4}}\end{align}\) and conc. \(\begin{align}HN{{O}_{3}}\end{align}\) the species which initiates the reaction is:

The correct IUPAC name of \(\begin{align}C{{u}_{2}}=CH-C{{H}_{2}}NHC{{H}_{3}}\end{align}\) is:

Which is the weakest base:

The correct order of basic strength for the following compounds is:

Methylamine reacts with \(\begin{align}HN{{O}_{2}}\end{align}\) to form

The structure of ‘C’ would be

Which of the following statement about primary amine is false:

Which of the following is most stable diazoniom salt?

Method by which aniline can not be prepared is:

In the chemical reaction:\(\begin{align}C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}+CHC{{l}_{3}}+3KOH\to \text{ }A+B+3{{H}_{2}}O\end{align}\) The compound A and B are respectively:

Considering the basic strength of amines in aqueous solution which one has the smallest \(\begin{align}p{{k}_{b}}\end{align}\) value?

Which of the following compound will give significant amount of meta product during mono-nitration reaction?

The final product C in the following sequence of reaction is:

A positive carbylamine test is given by

Which of the following reactions form benzylamine:

Which reagent among the following can affect the conversion? \(\begin{align}C{{H}_{3}}-C\equiv N\xrightarrow{{\,\,\,\,\,\,\,\,}}C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\end{align}\)

In which of the following amines, the first has lower pkb value than the second

Bromobenzene can be prepared from benzene diazonium chloride. When its is treated with

Direction: For given questions two statements are given-one labelled Assertion (A) and the other labelled Reason (R).
Assertion(A):n-Propylamine has higher boiling point than trimethylamine.
Reason(R): Among n-propylamine molecules, there is hydrogen bonding but there is not hydrogen bonding in trimethylamine.

Direction: For given questions two statements are given-one labelled Assertion (A) and the other labelled Reason (R).
Assertion(A): Aniline does not undergo Friedel Crafts reaction.
Reason(R): Friedel Crafts reaction is an electrophilic substitution reaction.

Match column 1 and column II
Column-I                                                                     Column-II
(A) Ammolysis                                                        (p) Amine with lesser no. of carbon atom
(B) Gabriel phthalimide                                       (q) Detection of primary amine
(C) Hoffmann bromide amide degradation     (r) Reaction of pthalimide with KOH and R—X
(D) Carbylamine reaction                                    (s) Reaction of alkyl halides with NH3

Match column 1 and column II
Column-I                                                      Column-II
(A) Benzene sulphonyl chloride                (p) zwitter ion
(B) Sulphanilic acid                                     (q) Hinsberg reagent
(C) Alkyl diazonium salts                           (r) Dyes
(D) Aryl diazonion salts                             (s) Conversion to alcohols